In This Chapter

► Keeping the facts in mind

► Digging into some practice questions

► Seeing how you did

Chapter 25 is chock-full of juicy little organic chemistry tidbits. Make sure that you have everything filed away in your brain properly by reviewing the concepts in this chapter and attempting the practice problems we include near the end of the chapter. Remember, although there are relatively few questions that directly test organic chemistry on the AP exam, a familiarity with the names and structures of organic compounds can help you to answer many other types of questions.

Making the Main Points Stick

To master the organic chemistry portion of the AP curriculum you need to memorize, memorize, memorize! Specifically, you must remember how to identify the 13 types of organic compounds, and 3 types of isomer listed in the sections below.

Important organic compounds

Listed below are the 13 types of organic compound most likely to appear on the AP exam, together with their naming rules. Make sure that you have a thorough understanding of what makes each unique before you move on.

Alkanes Are hydrocarbons containing only single bonds, Alkenes Contain double bonds and Alkynes Contain triple bonds.

Alkanes, alkenes, and alkynes are named by first numbering the longest carbon chain. Numbering starts at the end closest to the nearest multiple bond for alkenes and alkynes, while alkanes are numbered starting at the end that gives its branches the lowest numbers.

Substituents On all organic compounds are named with the suffix Yl And are preceded by the number of the main chain carbon atom from which they branch.

Cyclic aliphatic hydrocarbons Contain rings of carbon atoms and can contain multiple bonds. Aromatic hydrocarbons Also contain rings of carbon atoms, but the bonds between carbons alternate between double or triple bonds and single bonds.

Alcohols Are hydrocarbon chains that include a hydroxide (OH) group. They are named with the ending – ol.

Ethers Contain an oxygen atom in the midst of their carbon chain. They are named by naming the substituents on either side of the oxygen and then adding the ending Ether, As in ethyl methyl ether.

The final carbon atom in a Carboxylic acid Is double bonded to an oxygen atom as well as being single bonded to a hydroxide group. In condensed structural formulas, this configuration is written as R-COOH. Carboxylic acids are named by attaching the suffix -oic acid.

I Esters Are related to carboxylic acids in that they too have a carbon atom that is

Double bonded to one oxygen. This time, however, rather than also being bonded to a hydroxide group, the final carbon is bonded to a lone oxygen atom. This oxygen is itself bonded to another hydrocarbon chain, giving esters the condensed formula R-COOR. You name an ester by first naming the lower-priority hydrocarbon chain (the one not containing a carbon double bonded to oxygen) as a substituent and then attaching the suffix -oate To the high-priority chain.

I Aldehydes Are also similar to carboxylic acids in that their final carbon atom is double bonded to an oxygen atom, however in this case the fourth available carbon bond is taken up by a simple hydrogen atom rather than a hydroxide group, giving it the formula R-CHO. Aldehydes are named by attaching the suffix -al.

I Ketones Have the same structure as aldehydes, except that the double-bonded oxygen has infiltrated its way up to a midchain carbon. These compounds have the condensed formula ROR and are named with the suffix – one. Unlike esters, ketones contain uninterrupted carbon chains, so you need not worry about prefixes.

I Halocarbons Are hydrocarbon chains with a halogen substituent. The hydrocarbon portion is named normally, with the prefix Fluoro, chloro, bromo, Or Iodo Attached, depending on which halogen it contains.

I Amines Are hydrocarbon chains that contain an NH2 group and have the basic form R-NH2. They are named by naming the carbon chain as a substituent then adding the ending Amine.

Isomers

You will also be expected to be able to identify the following three types of isomer on the AP exam. Keep in mind that all isomers contain the same number and type of atoms, but their connectivities may be different.

I Structural isomers Contain the same number of atoms of carbon, hydrogen, oxygen, etc., but in different configurations.

I Stereoisomers Must have the same connectivities (in other words, all of their bonds need to be in the same order), and are divided into two categories — compounds that are nonsuperimposable mirror images of one another (enantiomers) and compounds that are superimposable mirror images of one another (diasteriomers).

I Geometric, Or Cis-trans, Isomers are stereoisomers that differ in the location of sub-stituent groups about a double bond. When the two groups are on the same side of the double bond, you are dealing with the cis isomer, while groups on opposite side of the double bond indicate a trans isomer.

Testing Your Knowledge

Apply your knowledge of the concepts outlined in Chapter 25 with these practice questions. Make sure that you are confident in your ability to distinguish between all of the different types of organic compounds and isomers before you attempt them, though! Remember that organic chemistry in particular involves a lot of memorization.

Questions 1 through 4 refer to the following types of organic compounds

(A)

Alcohols

(B)

Esters

(C)

Ethers

(D)

Aldehydes

(E)

Halocarbons

1. These organic compounds do not contain any oxygen atoms.

2. You may need to use the prefix Di In naming one of these organic compounds.

3. These organic compounds are known for having pleasant aromas.

4. These organic compounds are most closely related to ketones.

5. Of the following organic compounds, which is MOST soluble in water at 298K?

(A) Hexane

(B) Hexene

(C) Ethyl Methyl Ether

(D) Octanol

(E) Methanol

6. (a) Write out the condensed structural formula of 2-pentanone.

(b) Draw the complete structural formula of 2-pentanone, showing all atoms and bonds explicitly.

(c) Draw a complete structural formula for an isomer of pentanone.

Answers with Explanations

1. (E). The halocarbon is the only one of these organic compounds that doesn’t contain an oxygen atom.

2. (C). Ethers are named by naming the substituents on either side of the oxygen atom. If the groups on either side are the same, then the prefix Di – Is used as in CH3OCH3 (dimethyl ether).

3. (B). Esters are known for their pleasant aromas.

4. (D). Aldehydes and ketones both share a double C-O bond. In an aldehyde, the carbon double bonded to the oxygen is also bonded to a hydrogen atom, ending the carbon chain. In a ketone, the carbon chain continues beyond the double bond with oxygen.

5. (E). Following the "like dissolves like" rule (review solubility in Chapter 10 for more details), alcohols should be the most soluble in water among the compounds on this list because they have the same intermolecular forces as water. Octanol’s long nonpolar hydrocarbon chain, however, balances out the polar end of the molecule to some extent, making methanol the more soluble alcohol.

6. (a) CH3CH2CH2COCH3, 2-Pentanone is a five-carbon ketone, with the double-bonded oxygen on the second carbon. This means it has a condensed structural formula of CH3CH2CH2COCH3.

(b) Translate the condensed structural formula into a complete structural drawing, giving you

H H H O H I I I II I

H — C — C — C — C — C — H III I H H H H

(c) Any five-carbon ketone or aldehyde would be an acceptable isomer, as long as it still has the formula C5H10O. 3-pentanone and pentanal are two possibilities, both shown below.

Pentanae 3-pentanone

HHHHO HHOHH I I I I II I I II I I

H — C — C — C — C — C — H H — C — C — C — C — C — H

I I I I II II

H H H H H H H H

In This Chapter

^ Connecting chemistry you can’t see to chemistry you can see

^ Knowing how to predict the outcome of common chemical reactions

^ Predicting properties from position on the periodic table

There are a bunch of elements. These elements assemble into a ridiculously large variety of compounds. Then, just to make things more complicated, the compounds react with one another in different ways. To reduce the headache-inducing complexity of chemistry, it helps to know the lay of the land, to be familiar with a few details and themes that pop up over and over. Knowing these patterns helps you to develop a sense for whether certain compounds will react and what products they might generate. Also, sometimes things happen during a chemical reaction that are visible to the naked eye — solid particles or bubbles appear as if from nowhere — and these events give important clues as to the microscopic details of the reaction. Getting a feel for these kinds of things is what some people call "chemical intuition." In this chapter, you gain some chemical intuition so you can make predictions about how reactions will turn out.

Using Your Senses: Qualitative Aspects of Common Reaction Types

Seen from the outside, chemistry can seem weird. Mix two clear solutions and you never know what might happen. Maybe a solid (called a Precipitate) Will form, settling to the bottom of the beaker. Maybe gas will bubble out of the mixture. Maybe the final solution will be green. Maybe nothing will happen. How can you predict? Knowing which compounds you’re mixing is a good start. Armed with that information, you might be able to identify a likely reaction. The sections that follow list some common themes and patterns that might prove helpful on the AP chemistry exam.

Precipitation reactions

Precipitation occurs when an insoluble compound forms during the course of a reaction. Usually, the insoluble product is an ionic compound, formed between metal and nonmetal components. Being able to predict when precipitates form requires you to know which compounds are soluble and which are insoluble. Here are some helpful guidelines to help you sniff out which compounds are likely to precipitate and which are likely to stay in solution.

Precipitation reactions can occur when ionic compounds react, typically in Double displacement Reactions. In double displacement reactions, the cation components of ionic compounds swap anionic partners. So, if you are presented with two ionic reactant compounds,

AB(ag) + CD(a<7) — ? perform the following steps to complete the reaction and predict the products.

1. Swap the anion and cation partners to predict the reaction equation:

AB(aq) + CD(aq) — CB(?) + AD(?)

2. Next, Inspect the products to see if either or both are insoluble. Here are some basic rules for judging whether an ionic compound is soluble.

Compounds that contain the following ions are Soluble:

•NH4+

• Group IA (column 1) cations (that is, alkali metal ions) •NCV

• ClO3-, ClO2-

•CH3COO" (acetate ion, which can also be written as C2H3O2")

Compounds that contain the following ions are Usually soluble: •Cl-, Br- and I – (except When paired with Ag+, Pb2+, and Hg22+) •SO42- (except When paired with Ag+, Pb2+, Hg22+,Sr2+, Ca2+, and Ba2+)

Compounds that contain the following ions are Usually insoluble:

•OH- (that is, hydroxides, Except When paired with Group IA cations, Sr2+, Ca2+, and Ba2+)

•CO32-, PO43-, SO32-, and S2- (except When paired with Group I cations or NH4+)

3. After you determine whether you have a product that is insoluble, Rewrite the completed reaction equation as a Net ionic equation. Net ionic equations list only those components of the reaction that change state during the reaction. Ions in aqueous solution are listed separately, as ions, and not as part of a compound. Ions that appear on both the reactant and product sides (these are called Spectator ions) Are omitted. Thus,

Na2CO3(a<7) + Ba(NO3)2(aq) — ?

Undergoes a double displacement reaction, yielding:

4. Na2CO3(ag) + Ba(NO3)2(aq) — 2NaNO3(?) + BaCO3(?)Once you have the completed reaction and have assigned phases, Write a Total Ionic equation. The solubility rules state that the sodium nitrate pair is soluble, but when barium ion and carbonate ion combine, a solid precipitate forms. The resulting Total Ionic equation is

2Na+(ag) + CO32-(aq) + Ba2+(aq) + 2NO3-(aq) — 2Na+(aq) + 2NO3-(aq) + BaCO3(s)

5. Then, remove the spectator ions (Na+ and NO3-), leaving the Net Ionic equation:

CO32-(a< ) + Ba2+(a< ) — BaCO3(s)

Aside from precipitation reactions, you should be familiar with the basic patterns and common players in other reaction types, including gas-releasing reactions, reactions of hydrides and oxides, combustion reactions, reactions involving colored compounds, and acid-base reactions.

Gas-releasing reactions

Gas-releasing reactions often include decomposition or the reaction of metals/metal hydrides with water.

Gas-releasing decomposition can result from several processes:

Heating: Adding heat to some compounds can cause them to decompose (break apart) into several products, some of which are gases. For example

•CaCO3(s) — CaO(s) + CO2(g)

• 2KNO3(s) — 2KNO2(s) + O2(g)

• 2KClO3(s) — 2KCl(s) + 3O2(g)

•2H2O2(l) — 2H2O(l) + O2(g)

Electrolysis:. Molten ionic compounds can be decomposed when an electric current passes through them, releasing gas in the process:

2Na+(l) + 2Cl-(l) — 2Na(l) + Cl2(g)

Or, shown as two redox half-reactions

2Na+(l) + 2E – — 2Na(l) (reduction)

2Cl-(l) — Cl2(g) + 2e" (oxidation)

Unstable acids: Some weak acids are unstable and can decompose, especially if they aren’t in solution while heat is added.

H2SO3(s) — H2O(l) + SO2(g)

H2CO3(s) — H2O(l) + CO2(g)

Metals and metal hydride reactions

Metals and metal hydrides can release hydrogen gas when they react with water. These reactions result in a basic solution as hydrogen is taken from water leaving excess hydroxide ions:

LiH(s) + H2O(l) — Li+(aq) + OH-(aq) + H2(g) CaH2(s) + 2H2O(l) — Ca2+(aq) + 2OH-(aq) + 2H2(g) 2Na(s) + 2H2O(l) — 2Na+(aq) + 2OH-(aq) + H2(g)

Combustion reactions

Complete combustion occurs when hydrocarbons react with oxygen, forming carbon dioxide and water.

2C2H6(g) + 7O2(g) — 4CO2(g) + 6H2O(g) (ethane combusts) C2H4(g) + 3O2(g) — 2CO2(g) + 2H2O(g) (ethene combusts) 2C2H2(g) + 5O2(g) — 4CO2(g) + 2H2O(g) (ethyne combusts)

Oxide reactions

The pattern of an oxide reaction depends on whether it is a metal oxide or nonmetal oxide that reacts.

Metal oxides often react with water to produce basic solutions.

Li2O(s) + H2O(l) — 2Li+(a< ) + 2OH-(a< ) Nonmetal oxides often react with water to produce acidic solutions.

N2O5(s) + H2O(l) — 2NO3-(a< ) + 2H+(a< )

Colored compounds

Knowing something about which compounds are colored and what colors those compounds are can help you identify an unknown compound.

Salts and oxides that contain transition metals are often colored.

Ni-containing compounds are often green. Mn-containing compounds are often pink/purple. Colored soluble salts

• Fe-containing soluble salts are red and/or brown.

• Cu-containing soluble salts are blue and/or green.

• Co-containing soluble salts are blue. Colored insoluble salts

• Precipitates containing CrO42- (chrmate) are yellow.

• Precipitates containing Cr2O72- (dichromate) are orange.

• Precipitates containing OH – (hydroxide) are white.

• Precipitate of silver chloride (AgCl) is white.

• Precipitate of silver bromide (AgBr) is pale yellow.

Acids and bases

Acid-base reactions are very common and confuse many students. Key to understanding these reactions is being able to identify the acid and the base, and understanding how strong acids and bases behave differently from weak acids and bases. Acids and bases have predictable properties and reactions:

A strong acid is a weak base. A strong base is a weak acid.

The conjugate acid of a weak base is a weak acid. The conjugate base of a weak acid is a weak base.

Strong acids react with strong bases to form neutral salts and water. Strong acids react with weak bases to form acidic solutions. Strong bases react with weak acids to form basic solutions.

Surveying the Table: Predicting

Properties and Reactivity

There are two basic ways to look at the periodic table. You can pick a property and observe the trends in that property as you move left and right or up and down the table. Or, you can pick a row or column of the table and observe changes or the lack of changes in various properties as you move along the members of the column or row.

Reading trends across the table

The key periodic property is electronegativity, the tendency of an atomic nucleus to draw electrons toward itself within a bond. Electronegativity tends to increase to the right and upward within the main body of the periodic table, as shown in Figure 23-1. Electronegativity represents the result of a balance between an unbound atom’s ionization energy (tendency to lose an electron) and its electron affinity, the ability of an unbound atom to attract an electron. Ionization energy is the energy it takes to remove an electron from a gas-phase atom.

Trends in electronegativity, ionization energy (Figure 23-2), and electron affinity underlie other periodic trends, such as atomic radius (Figure 23-3), and metallic character (Figure 23-4). Atomic radius and metallic character are also largely determined by electronegativity, but both follow a pattern that is the mirror image of electronegativity, as each increases downward and to the left within the periodic table.

Increasing Ionization Energy

Figure 23-2-

Lonization energy increases upward and to the right within the periodic table.

IA

Low Energy

_ High Energy

VIIIA

1

H

IIA

IIIA

IVA

VA

VIA

VIIA

He

2

Li

Be

VIIIB

B

C

N

O

F

Ne

3

Na

Mg

IIIB

IVB

VB

VIB

VIIB

IB

IIB

Al

Si

P

S

Cl

Ar

R

4

K

Ca

Sc

Ti

V

Cr

Mn

Fe

C o

Ni

Cu

Zn

Ga

Ge

As

Se

Br

Kr

5

Rb

Sr

Y

Zr

Nb

Mo

Tc

Ru

Rh

Pd

Ag

Cd

Ln

Sn

Sb

Te

L

Xe

6

Cs

Ba

La

Hf

Ta

W

Re

Os

Lr

Pt

Au

Hg

Tl

Pb

Bi

Po

At

Rn

7

Fr

Ra

Ac

Increasing Size

Figure 23-3-

Atomic radius increases downward and to the left within the periodic table.

IA

1 2 3 4 5 6 7

Large Radii

Small Radii

VIIIA

H

IIA

IIIA IVA VA VIA VIIA

He

Li

Be

VIIIB

IIIB IVB VB VIB VIIBr-A-1 IB IIB

B

C

N

O

F

Ne

Na

Mg

Al

Si

P

S

Cl

Ar

K

Ca

Sc

Ti

V

Cr

Mn

Fe

C o

Ni

Cu

Zn

Ga

Ge

As

Se

Br

Kr

Rb

Sr

Y

Zr

Nb

Mo

Tc

Ru

Rh

Pd

Ag

Cd

Ln

Sn

Sb

Te

L

Xe

Cs

Ba

La

Hf

Ta

W

Re

Os

Lr

Pt

Au

Hg

Tl

Pb

Bi

Po

At

Rn

Fr

Ra

Ac

Increasing Metallic Character

Figure 23-4-

Metalli c c ha r a c te r increases downward and to the left within the periodic table.

IA

Least Metallic

VIIIA

H

IIA

IIIA

IVA

VA

VIA

VIIA

He

Li

Be

VIIIB

B

C

N

O

F

Ne

Na

Mg

IIIB

IVB

VB

VIB

VIIB

IB

IIB

Al

Si

P

S

Cl

Ar

R

•\

K

Ca

Sc

Ti

V

Cr

Mn

Fe

C o

Ni

Cu

Zn

Ga

Ge

As

Se

Br

Kr

Rb

Sr

Y

Zr

Nb

Mo

Tc

Ru

Rh

Pd

Ag

Cd

Ln

Sn

Sb

Te

L

Xe

Cs

Ba

La

Hf

Ta

W

Re

Os

Lr

Pt

Au

Hg

Tl

Pb

Bi

Po

At

Rn

Fr

Ra

Ac

Most Metallic

Finding patterns in columns and rows

The trends described in the previous section help explain why the elements within a vertical group of the periodic table tend to have properties similar to one another, whereas elements across a horizontal period display incremental changes in their properties, with a consistent trend.

Some groups hang together more closely than others. Within the periodic table, the two leftmost and two rightmost groups show the greatest kinship, keeping tightly to the characteristic properties of their respective vertical families. So, you can feel most confident making predictions based on the group similarity of leftmost columns (columns 1 and 2) and two columns on the right (columns 16 and 17). In addition, the elements in group VIIIA (column 18), the noble gases, have closely identifiable properties to one another. Note that two methods are used to identify columns in the periodic table. The older one uses A and B columns, the newer one has been adopted by the International Union of Pure and Applied Chemistry (IUPAC) and the American Chemical Society. Both will be used here.

Alkali metals (Group IA or 1)

• Elemental alkali metals are extremely reactive, and their cations are extremely unreactive.

• Alkali metals are the least electronegative, easily giving up electrons to form cations.

• In compounds, alkali metals have an oxidation number of +1.

• Though listed with Group IA, Hydrogen is not a metal And has some very different properties:

• In compounds with nonmetals, hydrogen assumes an oxidation number of +1.

• In compounds with metals, hydrogen assumes "hydride" form, with an oxidation number of -1.

Alkaline earth metals (Group IIA or 2)

• Alkaline earth metals are very reactive, and their cations are very unreactive.

• Alkaline earth metals have very low electronegativity.

• In compounds, alkaline earth metals have an oxidation number of +2. VIA or 16

• These elements are reactive because they have six electrons in their valence shell, not the stable, eight-electron valence shell of a noble gas.

• Ions of this group tend to have -2 charge. Halogens (Group VIIA or 17)

• Halogens are very electronegative, with the most electronegative at the top.

• In compounds, halogens usually have an oxidation number of -1.

• Halogens range in reactivity (though none are unreactive), with the most reactive at the top.

• Halogens form ionic compounds with metals and molecular compounds with nonmetals.

Noble gases (Group VIIIA or 18)

• Noble gases are the least reactive of the elements, due to their filled valence shells.

In This Chapter

^ Checking out the nomenclature of organic compounds

^ Taking in testable trends in the properties of organic compounds

^ Discovering isomerism and chirality

^ Running through common organic reactions

M W Rganic chemistry Is a huge subfield, and the AP chemistry exam merely scratches the

Surface of it. Still, a good grasp of the concepts and naming rules covered in this chapter could get you those few extra points needed to push your score up one grade on exam day.

Don’t spend too much time here if you’re still struggling with the big-point-gaining chapters earlier in this book. Your time is better spent polishing your knowledge of the concepts in those earlier chapters, if you’re struggling, because so few questions on the AP exam address organic chemistry. But if you feel comfortable with the big-point-gaining chapters, then tackle this chapter with vigor and get ready to file lots of new information away in that chemistry-packed brain of yours — organic chemistry is heavy on memorization.

In addition to the few questions on each AP exam directly addressing organic chemistry, a basic knowledge of the information in this chapter, including basic structure and naming. can aid you in answering many other questions on the exam. Organic compounds are sometimes used in questions testing concepts such as kinetics, stoichiometry, and colligative properties.

Naming Names: Nomenclature and Properties of Hydrocarbons

Any study of organic chemistry begins with the study of Hydrocarbons. Hydrocarbons are some of the simplest and most important organic compounds and they contain only hydrogen and carbon atoms. Organic compounds Are based on carbon skeletons. Carbon skeletons can be modified — you can dress them up with chemically interesting atoms like oxygen, nitrogen, halogens, phosphorous, silicon, or sulfur. This cast of atomic characters may seem like a rather small subset of the more than 100 elements in the periodic table. It’s true: Organic compounds typically use only a very small number of the naturally occurring elements. Yet these molecules include the most biologically important compounds in existence. In this section you will learn how to recognize and name all of the types of hydrocarbons that appear on the AP exam, including alkenes, alkanes, alkynes, and cyclic hydrocarbons.

Starting with straight-chain alkanes

Starting with straigi linear hydrocarbons

The simplest of the hydrocarbons fall into the category of Alkanes. Alkanes are chains of carbon atoms connected by single covalent bonds. Chapter 5 describes how single covalent bonds result when atoms share pairs of valence electrons. Carbon molecules have four valence electrons. So, carbon atoms are eager to donate their four valence electrons to cova-lent bonds so that they can receive four donated electrons in turn, filling their valence shell. In other words, carbon really likes to form four bonds. In alkanes, each of these is a single bond with a different carbon or hydrogen partner.

The simplest of the alkanes, called Continuous – Or Straight-chain alkanes, Consist of one straight chain of carbon atoms linked with single bonds. Hydrogen atoms fill all the remaining bonds. Other types of alkanes include closed circles and branched chains.

We begin with straight-chain alkanes because they make clear the basic strategy for naming hydrocarbons. From the standpoint of naming, the hydrogen atoms in a hydrocarbon are more or less "filler atoms." Alkanes’ names are based on the largest number of consecutively bonded carbon atoms. So, the name of a hydrocarbon tells you about that molecule’s structure. To name a straight-chain alkane, simply match the appropriate chemical prefix with the suffix -ane. The prefixes relate to the number of carbons in the continuous chain, which we list in Table 25-1.

Table 25-1

The Carbon Prefixes

Number of Carbons

Prefix

Chemical Formula

Alkane

1

Meth-

CH4

Methane

2

Eth-

C2H6

Ethane

3

Prop-

C3H8

Propane

4

But-

C4H10

Butane

5

Pent-

C5H12

Pentane

6

Hex-

C6H14

Hexane

7

Hept-

C7H16

Heptane

8

Oct-

C8H18

Octane

9

Non-

C9H20

Nonane

10

Dec-

C10H22

Decane

The naming method in Table 25-1 tells you how many carbons are in the chain. Because you know that each carbon has four bonds and because you are fiendishly clever, you can deduce the number of hydrogen atoms in the molecule as well. Any carbon at the end of a chain must be bonded to three hydrogens and all interior carbons must be bonded to two. Consider the carbon structure of pentane, for example, shown in Figure 25-1.

Figure 25-1: I I I I I

Pentane’s I I I I I

Carbon — C-C-C-C-C—

Skeleton.

Only four carbon-carbon bonds are required to produce the five-carbon chain of pentane. This leaves many bonds open — two for each interior carbon and three for each of the terminal carbons. These open bonds are satisfied by carbon-hydrogen bonds, thereby forming a hydrocarbon, as shown in Figure 25-2.

Figure 25-2:

Pentane’s hydrocarbon

Structure.

H HHH H

CCC C H

HHHHH

H

C

If you add up the hydrogen atoms in Figure 25-2, you get 12. So, pentane contains 5 carbon atoms and 12 hydrogen atoms.

As the organic molecules you study get more and more complicated, it will become more and more important to draw the molecular structure to visualize the molecule. In the case of straight-chain alkanes, the simplest of all organic molecules, you can remember a convenient formula for calculating the number of hydrogen atoms in the alkane without actually drawing the chain:

Number of hydrogen atoms = (2 x number of carbon atoms) + 2

You can refer to the same molecule in a number of different ways. For example, you can refer to pentane by its name (ahem. . . Pentane), By its molecular formula, C5H12, or by the complete structure in Figure 25-2. Clearly, these different names include different levels of structural detail. A Condensed structural formula Is another naming method, one that straddles the divide between a molecular formula and a complete structure. For pentane, the condensed structural formula is CH3CH2CH2CH2CH3. This kind of formula assumes that you understand how straight-chain alkanes are put together. Carbons on the end of a chain, for example, are only bonded to one other carbon, so they have three additional bonds to be filled by hydrogen and are labeled as CH3 in a condensed formula. Interior carbons are bonded to two neighboring carbons and have only two hydrogen bonds, and so are labeled CH2.

Going out on a limb: Making branched alkanes by substitution

Not all alkanes are straight-chain alkanes. That would be too easy. Many alkanes are so-called Branched alkanes. Branched alkanes differ from continuous-chain alkanes in that carbon chains substitute for a few hydrogen atoms along the chain. Atoms or other groups (like carbon chains) that substitute for hydrogen in an alkane are called Substituents.

Naming branched alkanes is slightly more complicated, but you need only to follow these simple set of steps to arrive at a proper (and often lengthy) name:

1. Count the longest continuous chain of carbons. Tricky chemistry problems often show branched alkanes with the longest chain snaking through a few branches instead of obviously lined up in a row. Consider the two carbon structures shown in Figure 25-3. The two are actually the same structure, drawn differently! Yikes. In either case, the longest continuous chain in this structure has eight carbons. That wasn’t hard — and yippee, now you already know the basic name for the compound. It is an octane.

Cc

C1 C2 C3 C4 C5 C

C6

B

C7

7

C8

8

C

Figure 25-3′ Ci – c2-c3 - c4- c5- cb – c7 – c

One carbon i i i

Structure | | |

Drawn two c c c

Different I

Ways. I

2. Number the carbons in the chain Starting with the end which is closest to a branch.

You can always check to be sure you have done this step correctly by numbering the carbon chain from the opposite end as well. The correct numbering sequence is the one in which the substituent branches extend from the lowest-numbered carbons. For example, as it is drawn and numbered in Figure 25-3, the alkane has substituent groups branching off of its third, fourth, and fifth carbons. If the carbon chain had been numbered backward, these would be the fourth, fifth, and sixth carbons in the chain. Because the first set of numbers is lower, the chain is numbered properly. The longest chain in a branched alkane is called the Parent chain.

3. Count the number of carbons in each branch. These groups are called Alkyl groups And are named by adding the suffix -yl To the appropriate alkane prefix (Table 25-1 awaits your visit). The three most common alkyl groups are the methyl (one carbon), ethyl (two carbons), and propyl (three carbons) groups. Figure 25-3 has two methyl groups, one ethyl group, and no propyl groups.

Be careful when you find yourself dealing with alkyl groups made up of more than just a few carbons. A tricky drawing may cause you to misnumber the parent chain!

4. Attach the number of the carbon from which each substituent branches to the front of the alkyl group name. For example, if a group of two carbons is attached to the third carbon in a chain, like it is in Figure 25-3, the group is called 3-ethyl.

5. Check for repeated alkyl groups. If multiple groups with the same number of carbons branch off the parent chain, do not repeat the name. Rather, include multiple numbers, separated by commas, before the alkyl group name. Also, specify the number of instances of the alkyl group by using the prefixes di-, tri-, tetra-, and so on. For example, if one-carbon groups (in other words, methyl groups) branch off carbons four and five of the parent chain, the two methyl groups appear together as "4,5-dimethyl."

6. Place the names of the substituent groups in front of the name of the parent chain In alphabetical order. Prefixes like di-, tri-, and tetra – do not figure into the alphabetizing. So, the proper name of the organic molecule in Figure 25-3 is 3-ethyl-4,5-dimethyloctane.

Note that hyphens are used to connect all the naming elements except for the last connection to the parent chain, which includes neither a hyphen nor a space (. . . dimethyl-octane is wrong). We recommend practicing alkanes till you get them in your sleep before moving on to other organic compounds!

Getting unsaturated: Alkenes and alkynes

Carbons can do more than engage in four single bonds. There’s more to organic molecules than substituent-for-hydrogen swaps:

When carbons in an organic compound fill their valence shells entirely with single bonds, we say the compound is Saturated.

When hydrocarbons contain carbons that bond to each other more than once, creating double or triple covalent bonds, we say these hydrocarbons are Unsaturated Because they have fewer than the maximum possible number of hydrogens or substituents.

For every additional carbon-carbon bond formed in a hydrocarbon, two fewer covalent bonds to hydrogen are formed.

When neighboring carbons share four valence electrons to form a double bond, the resulting hydrocarbon is called an Alkene. Alkenes are characterized by these chemically interesting double bonds, which are more reactive than single carbon-carbon bonds (see Chapter 7 for a review of sigma and pi bonding). Double bonds also change the shape of a hydrocarbon, because the Sp2 Hybridized valence orbitals assume a trigonal planar geometry, as shown by the carbons of ethene in Figure 25-4. Saturated carbon is Sp3 Hybridized and has tetrahedral geometry (again, see Chapter 7 to review hybridization).

H

\

Figure 25-4′

Ethene carbons.

H

H

H

Naming alkenes is slightly more complicated than naming alkanes. In addition to the number of carbons in the main chain and any branching substituents, you must also note the location of the double bonds in an alkene and incorporate that information into the name. Nevertheless, the essential naming strategy for alkenes is quite similar to that for alkanes:

1. Locate the longest carbon chain that includes the double bond, and number it, Starting at the end closest to the double bond. In other words, double bonds trump sub-stituents when it comes to numbering the parent chain. Build the name of the parent chain by using the same prefixes as used for alkanes (refer to Table 25-1), but match the prefix with the suffix -ene. A three-carbon chain with a double bond, for example,

Is called "propene."

2. Number and name substituents that branch off the alkene In the same way as done for alkanes (see the section earlier in this chapter, "Starting with straight-chain alkanes — linear hydrocarbons" for more on naming alkanes). List the number of the substituted carbon, followed by the name of the substituent. Separate the sub-stituent number and name with a hyphen.

3. Identify the lowest-numbered carbon that participates in the double bond, and put that number Between the substituent names and the parent chain name (sandwiched by hyphens), but after all the substituent names. For example, if the second and third carbons of a five-carbon alkene engage in a double bond, then the molecule is called 2-pentene, not 3-pentene. If that same molecule has a methyl substituent at the fourth carbon, then the molecule is called 4-methyl-2-pentene.

Alternately, and especially when there are substituents present, the position of an unsaturation is indicated between the prefix and suffix of the parent chain name. So, 4-methyl-2-pentene may also be written 4-methylpent-2-ene.

Alkynes Are hydrocarbons in which neighboring carbons share six electrons to engage in triple covalent bonds. The naming strategy for alkynes is the same as that for alkenes, except that the alkyne parent chain is named by matching the prefix with the suffix -yne.

An important consequence of the presence of multiple bonds in alkenes and alkynes is their marked increase in reactivity over alkanes. Generally speaking, the more multiple bonds a compound has, the more reactive it tends to be. This is because of the propensity of multiple bonded carbons to undergo addition reactions, which are discussed at the end of this chapter.

Rounding ‘em Up: Circling Carbons with Cyclics and Aromatics

The compounds we discuss earlier in this chapter are linear or branched. However, hydrocarbons can be circular, or Cyclical, Hydrocarbons There are two important categories of cyclical hydrocarbons:

Cyclic aliphatic Hydrocarbons Aromatic Hydrocarbons

Chemists sometimes divide hydrocarbons into aliphatic and aromatic categories to highlight important differences in structure and reactivity. Without going into more technical detail than is useful here, aliphatic molecules and aromatic molecules have significantly different electronic configurations (which electrons go into which orbitals). As a result, the two types of hydrocarbons typically undergo different kinds of reactions. In particular, they tend to undergo different kinds of substitution reactions, ones in which some atom or group substitutes for hydrogen.

Shutting the circle with cyclic aliphatic hydrocarbons

Cyclic aliphatic hydrocarbons are like the hydrocarbons that we discuss earlier in this chapter, except that they form a closed ring. The rules for naming these compounds build on the rules for naming alkanes, alkenes, and alkynes. For example, a cyclical six-carbon alkane includes the name "hexane," but is preceded by the prefix Cyclo-, Making the final name "cyclohexane."

A single substituent or unsaturation on a cyclic aliphatic hydrocarbon does not require a number. So, a single methyl-for-hydrogen substitution on cyclohexane yields a compound with the name methylcyclohexane. Likewise, a lone double bond unsaturation on cyclo-hexane yields a compound with the name cyclohexene.

Multiple substitutions or unsaturations require numbering. In these cases, the same rules apply for deciding the rank of substituents as applied to alkenes and alkynes. Triple bonds

Outrank double bonds. Double bonds outrank other substitutions. So, number the carbons in the way that respects these rankings and produces the lowest overall numbers. A cyclo-hexane molecule with two methyl substituents on neighboring carbons, for example, is called 1,2-dimethylcyclohexane.

Analyzing aromatic hydrocarbons

Aromatic hydrocarbons have special properties because of their electronic structure. Aromatics are both cyclic and conjugated:

I Cyclic: The carbons form a ringlike structure.

Conjugated: Conjugation results from an alternation of double or triple bonds with single bonds.

Aromatic molecules have clouds of Delocalized pi electrons, Electrons that move freely through a set of overlapping P Orbitals. The model aromatic compound is benzene. Because of its cyclical, conjugated bonding, pi electrons delocalize evenly into rings above and below the plane of the flat benzene molecule. Aromatic compounds are very stable compared to their aliphatic counterparts.

Numbering substituents on aromatics follows the same basic pattern as followed for cyclic aliphatic compounds. A single substituent requires no numbering, as in methylbenzene. Multiple substituents are numbered by rank, with the highest-ranked substituent placed on carbon number one, and proceeding in a way that results in the lowest overall numbers. A benzene ring with ethyl and methyl substituents situated two carbons away from one another, for example, would be called 1-ethyl-3-methylbenzene.

Decorating Skeletons: Organic Functional Groups

Surely you’ve noticed that in this chapter we have thus far limited our study of organic compounds to those made entirely of hydrogen and carbon. When studying the complex rules governing hydrocarbons, it is easy to forget that the periodic table contains more than 100 other elements. Although organic chemistry often concentrates on just a few of those elements, you’ll need to be familiar with many other compound types, and this time they’ll be made of more than just hydrogen and carbon. All of these exotic new compounds contain plain vanilla carbon chains, but each has a distinguishing feature composed of another, more exotic element. These embellishments are called Functional groups. These groups include noncarbon elements, and give organic compounds a dizzying array of different properties.

Because hydrocarbons are old news, we sometimes refer to them simply using the letter R, representing any hydrocarbon group: branched or unbranched, saturated or unsaturated.

Table 25-2 summarizes the other important organic compounds, their distinguishing features, and their endings. Some molecules contain more than one of these distinguishing features. Locations where one of these groups or a multiple bond appear are prime sites for reactions to occur. These sites are therefore called Functional groups. Carefully study the functional group column in Table 25-2 so you can recognize them quickly. These are the structures you should keep an eye out for later in this chapter.

Table 25-2

Functional Groups

Compound Name

Compound Formula

Functional Group

Prefix or Suffix

Alcohol

R-OH

-{-O H

-ol

Ether

R-O-R

— c O C —

Ether

Carboxylic acid

R-COOH

-oic acid

Ester

R-COOR

-oate

Aldehyde

R-CHO

‘O’

-al

Ketone

R-COR

‘O’

-one

Halocarbon

R-X

— c X:

(X = halogen)

-oro, omo, or odo

Amine

R-NH2

-rr

-amine

Alcohols: Hosting a hydroxide

Alcohols Are hydrocarbons with a hydroxide group attached to them. Their general form is R-OH. To name an alcohol, you simply count the longest number of consecutive carbon atoms in the chain, find its prefix Table 25-2, and then attach the ending -ol To that prefix. For example, a one-carbon chain with an OH group attached is methanol, two is ethanol, three is propanol, and so on. Substituents (groups branching off the main chain) must, as always, be accounted for, and you must specify the number of the carbon atom in the chain to which the hydroxyl (OH) group is attached. Begin your numbering at the end of the chain closest to the OH, and attach the number before the prefix + -ol. For example, the compound shown in Figure 25-5 contains a six-carbon chain with a hydroxyl group. Its base name is therefore

Hexanol. It has methyl groups (with one carbon each) on the second and fourth carbons and its OH group lies on the third carbon. Its proper name is therefore 2,4-dimethyl-3-hexanol.

Some alcohols are Polyhydroxyl, Or contain multiple hydroxyl groups. In order to avoid confusion with multiples of any substituent groups, the prefixes indicating numbers of hydroxyl groups in an alcohol are attached to the suffix Ol, Making them diols, triols, etc. For example, a four carbon alcohol containing hydroxyl groups on the first and third carbons is 1,3-butane-diol. The numbers indicating the locations of the hydroxyl groups must come before the base name but after any substituent groups.

_ HH OH H H H

Figure 25-5:

An example H-C-C-C-C-C-C-H

Of an alcohol.

_ H CH, H CH, H H

Ethers: Invaded by oxygen

Perhaps most commonly known for their use as early anesthetics, Ethers Are carbon chains that have been infiltrated by an oxygen atom. These oxygen atoms lie conspicuously in the middle of a carbon chain like badly disguised spies in an enemy camp and have the general formula R-O-R. Ethers are named by naming the alkyl groups on either side of the lone oxygen as substituent groups individually (adding the ending -yl To their prefixes), and then attaching the word Ether To the end. For example, the compound shown in Figure 25-6 is an ether with a methyl group (one carbon) on one side of the oxygen and an ethyl (two carbons) on the other. Placing the substituents in alphabetical order, the compound’s proper name is ethyl methyl ether.

Figure 25-6:

An example of an ether.

3

CH

Oxygen atoms in ethers are often surrounded by two identical alkyl groups, in which case the prefix Di – Must be attached to the name of that substituent. For example, an oxygen surrounded by two propyl groups (with three carbons each) is called dipropyl ether.

Carboxylic acids: R-COOH brings up the rear

Carboxylic acids Appear to be ordinary hydrocarbons until you reach the very last carbon in their chain, whose three ordinary hydrogens have been usurped by a double-bonded oxygen and a hydroxyl group (an OH group). This gives a carboxylic acid the general form R-COOH. These compounds are named by attaching the suffix -oic acid To the end of the prefix. For example, the compound shown in Figure 25-7 has four carbons, the last in the chain attached to a double-bonded oxygen and a hydroxyl group. The compound is therefore called butanoic acid. The hydrogen of the COOH group can pop off as H+ leaving an R-COO – ion, which is why these compounds are called acids. Carboxylic acids are a favorite compound type for AP exam writers because they are both organics and acids. It is important to note, however, that all car-boxylic acids are weak acids, so learn to spot them among acid lists and keep their relative weakness in mind.

Figure 25-7:

An example of a carboxylic acid.

H3C’

3

CH,

CH,

OH

O

C

Esters: Creating two carbon chains

What if the same double-bonded oxygen/hydroxyl pair from a carboxylic acid has infiltrated deeper into the hydrocarbon chain and is not on an end, but rather in the middle? In order to accomplish this, the COOH group must lose the hydrogen of its hydroxyl group (which, as an acidic hydrogen, is no problem) to open up a bond to which a second hydrocarbon can attach. A compound of this nature, with the general formula R-COOR, is called an Ester. Lots of nice, smelly coumpounds are esters, including the compounds that give pears, apples, and bananas their pleasant aromas.

Because the carbon chain in an ester is also broken by an oxygen, you’ll need to choose one carbon chain as a lowly substituent group and the other to bear the proud suffix of -oate. This high-priority group is always the carbon chain that includes the carbon double-bonded to one oxygen and single bonded to the other. The group on the other side of the single-bonded oxygen is named as an ordinary substituent. For example, the compound shown in Figure 25-8 is phenyl ethanoate, because the high priority group has two carbons and the low priority group is a benzene ring.

H3C

3

C

C

/

Figure 25-8:

An example of an ester.

—O

\

C HC

HCCH

HCCH

\ _ /

CH CH

That’s right! The low-priority group on the other side of the oxygen doesn’t have to be a hydrocarbon chain! It can be a ring or a metal as well. In Figure 25-8, this group is a benzene ring.

Aldehydes: Holding tight to one oxygen

Aldehydes Are much like carboxylic acids except that they lack the second oxygen in the COOH group. Their final carbon shares a single bond with its neighboring carbon, a double bond with an oxygen, and a single bond with hydrogen. Aldehydes are named with the suffix -al (not to be confused with the -ol Of alcohols) and have the general formula R-CHO. For example, the compound in Figure 25-9 is pentanal, a five-carbon chain with a double-bonded oxygen taking the place of two of the hydrogen bonds on the final carbon.

Figure 25-9:

An example of an aldehyde.

. CH,

-CH,

3

*CH,

CH

O

Ketones: Lone oxygen sneaks up the chain

Much like esters are to carboxylic acids, Ketones Share the same basic structure as aldehydes, except that their double-bonded oxygen can be found hiding out in the midst of the carbon chain, giving them the general form R-COR. Ketones are named by adding the suffix -one To the prefix generated by counting up the longest carbon chain. Unlike esters, however, the carbon chain of a ketone is not broken by the double-bonded oxygen group, making naming them much simpler. The compound shown in Figure 25-10, for example, is called simply 2-butanone; the number before the name specifies the number of the carbon to which the oxygen is attached.

Figure 25-10:

An example of a ketone.

H3C

CH

CH

O

Halocarbons: Hello, halogen!

Halocarbons Are simply hydrocarbons with a halogen or more tacked on to a carbon in place of a hydrogen atom. (A Halogen Is a group VIIA element.) Halogens in a halocarbon are always named as substituent groups — Fluoro, chloro, bromo, Or Iodo, One for each of the four halogens that form halocarbons (F, Cl, Br or I). The shorthand for a halocarbon is R-X, where X is the halogen. The compound shown in Figure 25-11 has two bromo groups attached, one to the second carbon and one to the third in a five-carbon alkane. Its official name is, therefore, 2,3-dibromopentane.

Br

CH

CH

Figure 25-11:

An example of a

Halocarbon.

H3C

3

CH

CH

Br

Amines: Hobnobbing with nitrogen

Amines Are as conspicuous as Waldo on the very first page of a Where’s Waldo Book. No tricksters wearing red-striped shirts are waiting to fool you among these organic molecules. Amines and their derivatives are the only compounds that you’ll encounter in basic organic chemistry that contain nitrogen atoms. Amines have the basic form R-NH2, and they’re named by naming the carbon chain as a substituent (with the ending -yl), And then adding the suffix -amine. The structure in Figure 25-12, for example, is called ethylamine because it’s a two-carbon ethyl chain with an amine group.

Figure 25-12:

An example of an amine.

-CH,

H, C

3

‘ NH,

Rearranging Carbons: Isomerism

How about this: Two organic molecules have identical chemical formulas. Each atom in one molecule is bonded to the same groups as in the other. They’re identical molecules, right? Wrong! (Mischievous chemistry gods point and snicker.) Many organic molecules are Iso-mers, Compounds with the same formula and types of bonds, but with different structural or spatial arrangements. Who cares about such subtle differences? Well, you might. Consider thalidomide, a small organic molecule widely prescribed to pregnant women in the late 1950s and early 1960s as a treatment for morning sickness. Thalidomide exists in two isomeric forms that rapidly switch from one to the other in the body. One isomer is very effective at combating morning sickness. The other isomer causes serious birth defects. Isomers matter.

Isomers can be confusing. They fall into different categories and subcategories. So, before committing your brain to a game of isomeric Twister, peruse the following breakdown: Keep in mind, however that all isomers, no matter what their specific classification, have both the same number and type of atoms.

Structural isomers Have identical molecular formulas but differ in the arrangement of bonds.

Stereoisomers Have identical connectivities — all atoms are bonded to the same types of other atoms — but differ in the arrangement of atoms in space.

• Diastereomers Are stereoisomers that are Not Non-superimposable mirror images of each other. Two types of diastereomers exist: Geometric isomers (or Cis-trans isomers) Are diastereomers that differ in the arrangement of groups around a double bond, or the plane of a ring. Conformers And Rotamers Are diastereomers that differ because of rotations about individual bonds (we don’t cover them in this book because they are beyond the scope of general chemistry).

• Enantiomers Are stereoisomers that Are Non-superimposable mirror images of each other.

You already know how to recognize and name stereoisomers appropriately by carefully studying the structure of the main chain and branching substituents. This section focuses on the trickier category: stereoisomers.

Picking sides with geometric isomers

Geometric isomers Or Cis-trans isomers Are a good place to start in the world of stereoisomers because they’re the easiest of the stereoisomers to understand. In the following sections, we explain how isomers relate to alkenes, alkanes that aren’t straight-chain, and alkynes.

Straight-chain alkanes are immune from geometric isomerism because their carbon-carbon single bonds can rotate freely. Unsaturate (or add another bond to) one of those bonds, however, and you’ve got a different story. Alkenes have double bonds that resist rotation. Furthermore, the Sp2 Hybridization of double-bonded carbons gives them trigonal planar bonding geometry (see Chapter 7 for an introduction to hybridization). The result is that groups attached to these carbons are locked on one side or the other of the double bond. Convince yourself of this by examining Figure 25-13.

Figure 25-13:

Cis And Trans Isomers ofan alkene.

H3C

3 ‘

H

\ / 3

H

H3C

3

H

\ /

H CH

A)

B)

In the left-hand structure of Figure 25-13, the carbon chain continues along the same side of the carbon-carbon double bond. Both methyl (-CH3) groups lie on the same side of the unsat-uration. This is called Cis Configuration. In the right-hand structure, the carbon chain swaps sides as it proceeds across the double bond. The methyl groups lie on opposite sides of the unsaturation. This is called a Trans Configuration.

Naming Cis-trans Isomers is simple. Attach the appropriate Cis – Or Trans – Prefix before the number referring to the carbon of the double bond. For example, the left-hand structure in Figure 22-1 is Cis-2-butene, while the structure on the right is Trans-2-butene.

Although straight-chain alkanes happily avoid isomerism by rotating merrily about their single bonds, the four bonds of sp3-hybridized carbons assume tetrahedral geometry. Detailed representations like the one shown for methane in Figure 25-14 reveal this geometry. In the structure of methane, the bonds depicted as straight lines run in the plane of the page. The bond drawn as a filled wedge projects outward from the page. The bond drawn as a dashed wedge projects behind the page. These filled and dashed wedge symbols are known as Stereo bonds Because they are helpful in identifying stereoisomers.

Figure 25-14:

Stereo bonds in methane.

C

HH

H

When alkanes close into rings, they can no longer freely rotate about their single bonds, and the tetrahedral geometry of sp3-hybridized carbons creates Cis-trans Isomers. Groups bonded to ring carbons are locked above or below the plane of the ring, as shown in Figure 25-15.

The figure depicts two different versions of trans-1,2-dimethylcyclohexane. In both versions, the adjacent methyl substituents are locked in Trans Positions, on opposite sides of the ring.

The upper set of structures shows the plane of the ring as seen from above, and highlights the Trans – Configuration of the methyl groups with stereo bonds.

The lower set of structures shows the same rings rotated 90 degrees downward and toward you.

H, C,

CH,

____■ ,

CH CH,

H3CV CH2

,

CH CH,

Figure 25-15:

Two isomers of Trans-1, ,-dimethyl-cyclo-hexane.

H3C

3

CH CH,

H3C

3

CH CH,

CH

The Trans Configuration of the methyl groups is most clear in the lower structures. The front-most methyl group is highlighted with explicit hydrogen atoms to emphasize its position above or below the plane of the ring.

Alkynes also contain carbon-carbon bonds that cannot rotate freely. However, the Sp Hybridization of the carbons in these bonds leads to linear bonding geometry. The two-carbon alkyne, ethyne, is shown in Figure 25-16. Each carbon locks three of its valence electrons into the axis of the triple bond. Each has only one valence electron remaining with which to bond to hydrogen. No Cis-trans Isomerism is possible in this scenario.

Figure 25-16:

No iso-merism is possible at the triple bonds of alkynes, such as ethyne.

■ CC-H

H

Changing Names: Some Common Organic Reactions

The carbon-based organic molecules presented in this chapter can morph into one another through chemical reactions. Such reactions are rather common, and the two most common types are substitution and addition reactions.

Alcohols are particularly prone to a chemical process called Substitution In which their OH group is replaced by a different atom. For example, the OH group on 2-pentanol can be replaced by the halogen fluorine, turning the alcohol into a halocarbon called 2-fluoro-pentane (see Figure 25-17).

OH

CH3— CH2— CH2— CH — CH3 + F2

3 2 2 3 2

Figure 25-17:

The

Process of F substitution.

CH3 CH2 CH2 CH CH3

3 2 2 3

The double bonds of alkenes also make them particularly likely to react with other compounds through a process called Addition. If the double bond between two carbon molecules is broken, it allows each of those two carbon atoms to form a bond with another atom or molecule. The reaction shown in Figure 25-18, for example, shows water being added across the double bond of 1-hexene. The water molecule itself is split into two pieces — simple hydrogen and a hydroxide — and each of them is added to one of the two carbons that used to share a double bond, forming either 1-hexanol or 2-hexanol.

Figure 25-18: HOH

The process

Of addition. H2C CH — CH2— CH2— CH2— CH3

2 2 2 2 3

H3C

3

OH

CH CH

CH

CH

CH

The 5th Wave_By Rich Tennant

"Your formula Јor a carbohydrate is close, but not entirely accurate. I’m pretty sure carbohydrates consist oЈ carbon, hydrogen, oxygen, sour cream, and bacon bits.*

In this part. . .

/n earlier times, chemists relied extensively on high-tech instruments like "eyes" and "noses" and so forth. Chemistry used to be largely a descriptive science, without the extensive calculations and precise measurements that characterize it today. Qualitative observations are still a useful part of chemistry, and understanding qualitative patterns in things like color and solubility is a big part of developing an elusive and prized skill called "chemical intuition." This part gives an overview of descriptive chemistry as it applies to the AP Chemistry exam. Organic chemistry is another branch of chemical science with deep roots and time-honored, qualitative traditions. But beyond its history, organic chemistry is a huge modern enterprise with massive application in medicine and industry, among other things. We close this part by giving you a glimpse into organic chemistry, the chemistry of carbon-based compounds, preparing you for its inevitable appearance on the exam.

In This Chapter

Making sure you remember what’s important ^ Practicing with questions

^ Getting your questions answered and explained

LEscriptive chemistry, as you may have gathered from Chapter 23, is perhaps the most memorization-intensive area covered by the AP chemistry exam. But fight the impulse

To sweep it under the rug — having an intuitive feel for periodic trends and the broad patterns of common chemical reactions is an invaluable asset. Help gel your chemical intuition by reviewing the highlights of Chapter 23 and applying your insights to the practice questions provided here.

Keeping the Important Stuff Straight

Because descriptive chemistry includes a lot of "just-have-to-know" details, this summary of ideas from Chapter 23 is one that you’ll probably want to review well and often, even more than the summaries of many other chapters. To make the task easier, the bits and pieces are grouped into categories that reflect specific reaction types or specific perioidic patterns. Focus on one category at a time, attempting to master each one before moving on to the others. That way, you won’t lose your way in the swirl of details.

Precipitation reactions

Much of the previously mentioned memorization has to do with knowing which ionic compounds are soluble in water and which are not. You need this knowledge to predict the phases of products of ionic double displacement reactions, so you can properly write net ionic equations.

Here is a summary of solubility rules and the process of formulating net ionic equations:

Precipitation reactions can occur when ionic compounds react, typically in Double displacement Reactions.

Compounds that contain the following ions are soluble: NH4+, Group IA cations, NO3-, ClO3-, ClO2-, CH3COO-.

Compounds that contain the following ions are usually soluble: Cl-, Br-, and I – (except with Ag+, Pb2+, and Hg22+); SO42- (except with Ag+, Pb2+, Hg22+,Sr2+, Ca2+, and Ba2+).

Compounds that contain the following ions are usually insoluble: OH – (except with Group IA cations, Sr2+, Ca2+, and Ba2+); CO32-, PO43-, SO32-, and S2- (except with Group IA cations or NH4+).

Net ionic equations list only those components of the reaction that change state during the reaction. Spectator ions, those ions that appear in the same fashion on both the reactant and product sides, are omitted.

Patterns of common reaction types

Beyond precipitation, it pays to know the patterns of common reaction types that you’ll likely encounter on the AP exam, including gas-releasing reactions, complete combustion, reactions of oxides, and acid-base reactions.

Here is a concise summary of the patterns you can expect from the most commonly tested reaction types:

Gas-releasing decomposition can result from heating, electrolysis, and unstable acids (especially H2CO3 and H2SO4).

I Metals and metal hydrides can release hydrogen gas when they react with water, producing a basic solution (excess hydroxide ion).

I Combustion occurs when hydrocarbons and other compounds containing carbon-hydrogen bonds, such as alcohols, react with oxygen, forming carbon dioxide and water.

I Metal oxides often react with water to produce basic solutions. I Nonmetal oxides often react with water to produce acidic solutions. I Salts and oxides that contain transition metals are often colored. I Acids and bases

• A strong acid is a weak base. A strong base is a weak acid.

• The conjugate anion of a strong acid is a Very Weak base. The conjugate cation of a strong base is a Very Weak acid.

• The conjugate acid of a weak base is a weak acid. The conjugate base of a weak acid is a weak base.

• The conjugate acid of a weak base is a Stronger Acid Than the base And the conjugate base of of a weak acid is a Stronger Base Than the acid.

• Strong acids react with strong bases to form neutral salts and water.

• Salts of weak acids or bases react in water to form weakly acidic or basic solutions.

Periodic trends and group properties

The periodic table is periodic for a reason — the elements of the table are arranged to reflect recurring patterns in the properties of the elements. Those patterns emerge from trends in the number of valence electrons held by the elements. Although learning these patterns requires a bit of initial memorization, knowing them saves you a load of memorization in the long run.

Here are the key periodic trends and the properties of important groups of elements:

Electronegativity, electron affinity, and ionization energy tend to increase upward and to the right within the main body of the periodic table.

Atomic radius and metallic character tend to increase downward and to the left within the main body of the periodic table.

Alkali metals (Group IA) Are extremely reactive, and their cations are extremely unre-active; they are the least electronegative elements; they have an oxidation number of + 1 within compounds.

Hydrogen is not a metal: In compounds with nonmetals, hydrogen has oxidation number +1; in compounds with metals, hydrogen has oxidation number -1.

Alkaline earth metals (Group IIA) Are very reactive, and their cations are very unreac-tive; they have very low electronegativity; they have an oxidation number of +2 within compounds.

Halogens (Group VIIA) Are very electronegative and range in reactivity, with the most electronegative and most reactive at the top; they form ionic compounds with metals and molecular compounds with nonmetals; they usually have an oxidation number of -1 within compounds.

Noble gases (Group VIIIA) Are extremely unreactive. The larger atoms (Kr and Xe) Can Form compounds with strongly electronegative atoms such as fluorine and oxygen.

Testing Your Knowledge

You put in the hard work of climbing to the top of Chapter 23. Now peer from the heights, seeing what you can see from the summit. Don’t foget to make full use of the periodic table as you work these questions. The more you use it, the quicker you will find your way around it.

1. Which of the following statements are true about the combustion of propane, C3H8?

(I) Oxygen, O2, is produced.

(II) Total moles of products outnumber total moles of reactants.

(III) Products can react to form carbonic acid, H2CO3.

(A) I only

(B) II only

(C) III only

(D) I and II only

(E) II and III only

2. Which element has the greatest electronegativity?

(A)

Be

(B)

Ba

(C)

Fe

(D)

O

(E)

Po

3. Which element has the most metallic character?

(A) Si

(B) Pb

(C) Fr

(D) K

(E) Mg

4. Which element has the lowest ionization energy?

(A) H

(B) Li

(C) Ne

(D) Cs

(E) Ra

5. Which of the following pairs of solutions produce a precipitate if mixed?

(I)

HBr(aq)

And

Ca(OH)2(aq)

(II)

Pb(NO3)2(aq)

And

LiI(a<7)

(III)

(NH4)3PO4(aq)

And

MgCl2(aq)

(A)

I only

(B)

II only

(C)

III only

(D)

I and II only

(E)

II and III only

6. Which of the following reactants are least likely to yield a gaseous product?

(A) LiClO3 and heat

(B) Ca(OH)2 and heat

(C) NaH and H2O

(D) K and H+

(E) Li and H2O

7. Which mixture(s) will produce a solution with pH < 7?

(I)

P4O10 and H2O

(II)

MgO and H2O

(III)

SrH2 and H2O

(A)

I only

(B)

II only

(C)

III only

(D)

II and III only

(E)

I, II, and III

8. Which of the following manipulations increase the solubility of calcium carbonate, CaCO3(s), In aqueous solution?

(I)

Decrease temperature

(II)

Decrease pH

(III)

Add Na2CO3

(A)

I only

(B)

II only

(C)

III only

(D)

I and II only

(E)

None

Questions 9 through 13 refer to the following set of choices. Pick the Best Answer in each case.

(A) Transition metals

(B) Strong acids conjugates

(C) Weak acids

(D) Salts

(E) Hydrides

9. Are weak bases 10. Often form colored compounds. 11. Result from neutralization reactions

12. Release hydrogen gas in the presence of wate

13. Are conjugates of weak base

14. Which of the following represent(s) a net ionic equation?

(I) Zn(s) + HCl(a<7) — ZnCl2(aq) + H2(g)

(II) CaCO3(s) + 2H+(aq) + 2Cl-(aq) — Ca2+(aq) + 2Cl-(aq) + H2O(l) + CO2(g)

(III) Ag+(a< ) + Cl-(a< ) — AgCl(s)

(A) I only

(B) II only

(C) III only

(D) I and II only

(E) II and III only

Questions 15 through 16 refer to the diagram of an electrolytic cell in Figure 24-1:

- +

Figure 24-1:

Electolytic cell.

N ri

15. Electrons travel out of the liquid along this wire:

(A) 1

(B) 2

(C) 1 and 2 simultaneously

(D) Neither 1 nor 2

(E) Alternates between 1 and 2

16. If molten LiCl is the liquid indicated by 5, then the following is true:

(I) Solid metal may accumulate at 3.

(II) Cl2(g) may bubble from 4.

(III) Li2(g) may bubble from 3.

(A) I only

(B) II only

(C) III only

(D) I and II only

(E) II and III only

1

2

3

4

5

Checking Your Work

If you feel like a few of your answers may have been less than perfect, check them against the answers and explanations below. If you’re certain that you nailed the questions, check your answers anyway, if only to revel in your perfection.

1. (E). Combustion of a hydrocarbon (like propane) involves a combination reaction with oxygen gas, yielding carbon dioxide and water products. Here’s the balanced equation for the combustion of propane:

C3H8(g) + 5O2(g) —3CO2(g) + 4H2O(I)

From the balanced equation, it’s clear that oxygen is consumed, not produced. Moreover, the moles of products (3 + 4 = 7) outnumber the moles of reactants (1 + 5 = 6). Finally, the carbon dioxide and water products can undergo a further reaction to form carbonic acid:

CO2(g) + H2O(I) — H2CO3(ag)

2. (D). Overall, electronegativity increases upward and to the right on the periodic table.

3. (C). Overall, metallic character increases downward and to the left on the periodic table.

4. (D). Overall, ionization energy increases upward and to the right on the periodic table (just like electronegativity).

5. (E). HBr and Ca(OH)2 are a strong acid and a strong base, respectively, that undergo a neutralization reaction to produce water and the soluble salt, CaBr2. Although the nitrate salt of lead is soluble (like virtually all nitrate salts), most other lead salts (like PbI2) are insoluble. Although ammonium phosphate is soluble (like virtually all ammonium salts), only Group IA and ammonium salts of phosphate are soluble — other phosphate salts (like Mg3(PO4)2) are insoluble.

6. (B). Chlorate (ClO3-) salts tend to decompose with heat, yielding oxygen gas. Ionic compounds containing hydroxide (OH-) do not tend to decompose with heat. Metal hydrides (like NaH) tend to produce hydrogen gas when they react with water. Reactive metals (like Group IA and Group IIA metals) tend to react with acid (H+) to produce hydrogen gas. Reactive metals also tend to react with water to produce hydrogen gas.

7. (A). Nonmetal oxides (like P4O10) tend to react with water to produce acidic (pH < 7) solutions:

P4O10(g) + 6H2O(I) — 12H+(a<7) + 4PO43"(a<7)

Metal oxides (like MgO) tend to react with water to produce basic (pH > 7) solutions: MgO(s) + H2O(I) — Mg2+(a<7) + 2OH"(a<7)

Metal hydrides (like SrH2) tend to react with water, releasing hydrogen gas and producing a basic solution:

SrH2(s) + 2H2O(I) — Sr2*(aq) + 2OH"(ag) + 2H2(g)

8. (B). Decreasing temperature usually decreases the solubility of solid solutes. Adding CO32-anion by means of sodium carbonate decreases the solubility of CaCO3 due to the common ion effect, in which the added carbonate shifts the equilibrium toward undissolved CaCO3.

Decreasing pH increases CaCO3 solubility because the added H+ undergoes a secondary reaction with CO32-, shifting the overall equilibrium toward dissolved CaCO3:

CaCO3(s) + H2O(I) — Ca2+(ag) + CO32′(aq)

H*(aq) + CO32"(ag) — HCO3-(ag)

9. (B). Conjugates of strong acids are Very Weak bases.

10. (A). Transition metals are notorious for forming intensely colored coordination complexes.

11. (D). In a neutralization reaction, acid and base reactants react to form a salt and water.

12. (E). Hydrides (especially metal hydrides) tend to react with water to produce hydrogen gas, H2.

13. (C). Weak acids are the conjugate acids Of Weak bases.

14. (C). To generate a net ionic equation, list dissolved (soluble) compounds as dissociated ions. Then, cancel any spectator ions, which are those ions that appear in identical form on both sides of the reaction equation. What remains is the net ionic equation. For example:

AgNO3(ag) + NaCl(a<7) — NaNO3(ag) + AgCl(s)

Ag+(ag) + NO3"(a<7) + Na*(aq) + Cl~(aq) — Na*(aq) + NO3"(ag) + AgCl(s) Ag+(ag) + Cl"(a<7) — AgCl(s)

15. (B). The positive and negative signs at the top of the figure indicate the polarity of the voltage source for the electrolytic cell. Because electrons have negative charge, they migrate out of the liquid toward the positive pole along 2, and into the liquid away from the negative pole along 1.

16. (D). If the liquid indicated by 5 is molten LiCl, then the salt is dissociated into Li+ cations and Cl – anions. Molten salts can be decomposed by electrolysis in this kind of cell. The electrode at 3 acts as a cathode, delivering electrons to Na+( ) cations, which deposit there as Na(s) metal. The electrode at 4 acts as an anode, accepting electrons from Cl-(l) anions, which react with one another to form Cl2(g) at the electrode.